Python Program to Check Armstrong Number.

Example:

Input: num = 1634
Output: 1634 is an Armstrong Number.

Explanation: 1*1*1*1 + 6*6*6*6 + 3*3*3*3 + 4*4*4*4 = 1634

Input: num = 130
Output: 130 is not an Armstrong Number.

Explanation: 1*1*1 + 3*3*3 + 0*0*0 = 28

def is_armstrong_number(number):
    # convert the number to a string and find the number of digits
    num_str = str(number)
    num_digits = len(num_str)

    # initialize a variable to store the sum of the digits raised to the power of the number of digits
    sum_of_digits = 0

    # loop through each digit in the number
    for digit in num_str:
        # raise the digit to the power of the number of digits and add it to the sum
        sum_of_digits += int(digit) ** num_digits

    # return True if the sum is equal to the number, and False otherwise
    return sum_of_digits == number

# take input from the user
number = int(input("Enter a number: "))

# check if the number is an Armstrong number
if is_armstrong_number(number):
    print(number, "is an Armstrong number.")
else:
    print(number, "is not an Armstrong number.")

Enter a number: 153
153 is an Armstrong number.

• Time Complexity: O(log n)
• Space Complexity: O(1)