Check Leap Year in Java.

In this article, we are going learn how to check if the given year is a leap year or not using Java Programming and we will use Java if-else condition to solve this problem.

Leap Year are those Year in which we have 366 days whereas a normal Year contains 365 days. In leap year, the month Feburary contain 29 days. (alert-success)

Algorithm for Leap Year.

Below algorithm used to check if a year is a leap year or not:

• Take an input year from the user.
• If the year is evenly divisible by 4, go to step 3. Otherwise, go to step 6.
• If the year is evenly divisible by 100, go to step 4. Otherwise, go to step 5.
• If the year is evenly divisible by 400, go to step 5. Otherwise, go to step 6.
• The year is a leap year (it has 366 days).
• The year is not a leap year (it has 365 days).

Java Code Implementation to Find Leap Year.

import java.util.Scanner;

public class LeapYear {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        int year;
        
        // Prompt user to enter a year
        System.out.print("Enter a year: ");
        year = input.nextInt();
        
        // Check if the entered year is a leap year
        if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) {
            System.out.println(year + " is a leap year");
        }
        else {
            System.out.println(year + " is not a leap year");
        }
    }
}

Enter a year: 2020
2020 is a leap year

Enter a year: 2022
2020 is not a leap year