Given a number num, you need to write a Python Program to print the number in reverse.
Example: Input: num = 1372 Output: 2731 Input: num = 901 Output: 109
Reverse a number using String Slicing in Python.
- The function takes the input num and converts it to a string.
- The function then uses slicing to reverse the string and returns the result as an integer.
- The program then takes input from the user and stores it in the num variable.
def reverse_number(num): return int(str(num)[::-1]) # take input from the user num = int(input("Enter a number: ")) # reverse the number rev = reverse_number(num) # print the reversed number print("The reversed number is", rev)
Enter a number: 1348
The reversed number is 8431
Reverse a number using a while loop in Python.
- The program defines a function reverse_number to reverse a given number.
- The function initializes two variables rev and rem to store the reversed number and the remainder of the number.
- The function then uses a while loop to reverse the number digit by digit.
- In each iteration, the function calculates the remainder of the number by dividing it by 10 and stores it in rem.
- The function then multiplies the current value of rev by 10 and adds rem to it.
- The function then updates the value of num by dividing it by 10.
- The function repeats these steps until num is 0.
def reverse_number(num): rev = 0 while num > 0: rem = num % 10 rev = rev * 10 + rem num = num // 10 return rev # take input from the user num = int(input("Enter a number: ")) # reverse the number rev = reverse_number(num) # print the reversed number print("The reversed number is", rev)
Enter a number: 034
The reversed number is 43Reverse a number using Recursion in Python.
- The function takes two inputs: num and rev, where num is the number to be reversed and rev is the reversed number so far.
- The function uses an if statement to check if num is 0. If num is 0, the function returns rev.
- If num is not 0, the function calculates the remainder of num by dividing it by 10 and stores it in rem.
- The function then calls itself with num // 10 and rev * 10 + rem as inputs and returns the result.
def reverse_number(num, rev=0): if num == 0: return rev rem = num % 10 return reverse_number(num // 10, rev * 10 + rem) # take input from the user num = int(input("Enter a number: ")) # reverse the number rev = reverse_number(num) # print the reversed number print("The reversed number is", rev)
Enter a number: 2034
The reversed number is 4302- Time Complexity: O(n) where n is the number of digits that the number contains.
- Space Complexity: O(n) stack space is required for performing recursion.
